288 fiber optic cable size

The diameter of a 288-fiber optic cable is typically around 12–15 mm, depending on the design and manufacturer.Cable Structure and DiameterA 288-fiber cable is often constructed using 12 tubes of 24 fibers each or 8 tubes of 36 fibers, depending on whether the fibers are arranged in ribbons or loose tubes. Each tube contains multiple fibers, and the tubes are bundled around a central strength member with a protective jacket. This design allows high fiber density while maintaining flexibility and durability .Typical DimensionsLoose-tube gel-free outdoor cables: The overall diameter usually ranges from 12 mm to 15 mm for standard 288-fiber designs, with variations depending on the jacket thickness and water-blocking materials .Ribbon-based high-density cables: When using hard ribbons, the cable may be slightly larger to accommodate the ribbon stacking and central spacers, but it remains compact relative to the fiber count .ConsiderationsInstallation: The cable's diameter affects bend radius, conduit fill, and handling. A 288-fiber cable typically requires a minimum bend radius of 15 times the cable diameter, which translates to roughly 180–225 mm for a 12–15 mm cable .Weight and flexibility: High fiber density increases stiffness, so careful planning is needed for aerial, duct, or vault installations. In summary, while the exact diameter can vary slightly by manufacturer and cable type, a 288-fiber optic cable generally measures between 12 mm and 15 mm in diameter, balancing high fiber count with manageable size for installation .